The salaries of three friends Sita, Gita and Mita are initially in the ratio , respectively. In the first year, they get salary hikes of , and , respectively. In the second year, Sita and Mita get salary hikes of and , respectively, and the salary of Gita becomes equal to the mean salary of the three friends. The salary hike of Gita in the second year is
The salaries of three friends Sita, Gita and Mita are initially in the ratio , respectively. In the first year, they get salary hikes of , and , respectively. In the second year, Sita and Mita get salary hikes of and , respectively, and the salary of Gita becomes equal to the mean salary of the three friends. The salary hike of Gita in the second year is
Solution
We need to track salary changes over two years and find Gita's second-year hike when her salary equals the mean of all three salaries.
Initial ratio: Sita : Gita : Mita = 5 : 6 : 7
When working with ratios, we can use any common multiplier. Let's use the ratio values directly:
Sita's initial salary = 5 units
Gita's initial salary = 6 units
Mita's initial salary = 7 units
First year hikes: 20%, 25%, and 20% respectively
To find salary after a percentage increase, multiply by (1 + percentage/100)
Sita: 5 × (1 + 20/100) = 5 × 1.20 = 6 units
Gita: 6 × (1 + 25/100) = 6 × 1.25 = 7.5 units
Mita: 7 × (1 + 20/100) = 7 × 1.20 = 8.4 units
After first year: 6 : 7.5 : 8.4
Second year hikes: Sita gets 40%, Mita gets 25%, Gita's salary = mean of all three
Sita: 6 × (1 + 40/100) = 6 × 1.40 = 8.4 units
Mita: 8.4 × (1 + 25/100) = 8.4 × 1.25 = 10.5 units
Gita: Let's call this x units (we need to find this)
After second year: 8.4 : x : 10.5
Given: Gita's salary = Mean of all three salaries
Mean =
Mean of three salaries =
Since Gita's salary equals the mean:
Therefore: Gita's salary after second year = 9.45 units
Gita's salary change:
Before second year: 7.5 units
After second year: 9.45 units
Increase: 9.45 - 7.5 = 1.95 units
Percentage increase =
Percentage increase =
Gita's salary hike in the second year is 26%