Skip to main contentSkip to solution

In an examination, Rama's score was one-twelfth of the sum of the scores of Mohan and Anjali. After a review, the score of each of them increased by 66. The revised scores of Anjali, Mohan, and Rama were in the ratio 11:10:311:10:3. Then Anjali's score exceeded Rama's score by

Solution

✅ Correct Option: 1

Let us represent the original scores with variables:

Rama's original score = R

Mohan's original score = M

Anjali's original score = A

Rama's score was one-twelfth of the sum of Mohan's and Anjali's scores:

R=112(M+A)R = \frac{1}{12}(M + A)


After each score increased by 6, the ratio became 11:10:3 (Anjali : Mohan : Rama).

When we have a ratio like 11:10:3, it means:

Anjali's revised score = 11x (for some value x)

Mohan's revised score = 10x

Rama's revised score = 3x


Since each score increased by 6, the original scores were:

Anjali's original score = 11x - 6

Mohan's original score = 10x - 6

Rama's original score = 3x - 6


Substituting into our first equation:

R=112(M+A)R = \frac{1}{12}(M + A)

(3x−6)=112[(10x−6)+(11x−6)](3x - 6) = \frac{1}{12}[(10x - 6) + (11x - 6)]

3x−6=112(21x−12)3x - 6 = \frac{1}{12}(21x - 12)

3x−6=21x−12123x - 6 = \frac{21x - 12}{12}

12(3x−6)=21x−1212(3x - 6) = 21x - 12

36x−72=21x−1236x - 72 = 21x - 12

36x−21x=72−1236x - 21x = 72 - 12

15x=6015x = 60

x=4x = 4


Now we can find the original scores:

Anjali's original score = 11x - 6 = 11(4) - 6 = 44 - 6 = 38

Rama's original score = 3x - 6 = 3(4) - 6 = 12 - 6 = 6

The difference = 38 - 6 = 32


Therefore, Anjali's score exceeded Rama's score by 32.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question