In 2010, a library contained a total of 11500 books in two categories - fiction and non-fiction. In 2015, the library contained a total of 12760 books in these two categories. During this period, there was 10% increase in the fiction category while there was 12% increase in the non-fiction category. How many fiction books were in the library in 2015?
In 2010, a library contained a total of 11500 books in two categories - fiction and non-fiction. In 2015, the library contained a total of 12760 books in these two categories. During this period, there was 10% increase in the fiction category while there was 12% increase in the non-fiction category. How many fiction books were in the library in 2015?
Solution
We can see we're dealing with a system of equations involving percentage increases.
Let's define our variables clearly:
Let = number of fiction books in 2010
Let = number of non-fiction books in 2010
The problem statement seems to be missing the total for 2010, but from the context and solution, it should be 11500 books.
When something increases by 10%, the new amount becomes 110% of the original, which we write as 1.1 times the original. Similarly, a 12% increase means 1.12 times the original.
From the given information:
Total books in 2010:
Total books in 2015:
The first equation by 1.1:
Subtract this from the second equation:
When we subtract, the terms cancel out, leaving us with just the terms. This is a clever way to eliminate one variable quickly.
Using the first equation:
Fiction books in 2015:
There were 6600 fiction books in the library in 2015.
When dealing with percentage change problems, always convert percentages to decimals (10% increase = multiply by 1.1) and look for opportunities to eliminate variables by strategic multiplication and subtraction.