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In 2010, a library contained a total of 11500 books in two categories - fiction and non-fiction. In 2015, the library contained a total of 12760 books in these two categories. During this period, there was 10% increase in the fiction category while there was 12% increase in the non-fiction category. How many fiction books were in the library in 2015?

Solution

✅ Correct Option: 1

We can see we're dealing with a system of equations involving percentage increases.

Let's define our variables clearly:

Let xx = number of fiction books in 2010

Let yy = number of non-fiction books in 2010

The problem statement seems to be missing the total for 2010, but from the context and solution, it should be 11500 books.


When something increases by 10%, the new amount becomes 110% of the original, which we write as 1.1 times the original. Similarly, a 12% increase means 1.12 times the original.

From the given information:

Total books in 2010: x+y=11500x + y = 11500

Total books in 2015: 1.1x+1.12y=127601.1x + 1.12y = 12760


The first equation by 1.1:

1.1x+1.1y=126501.1x + 1.1y = 12650


Subtract this from the second equation:

(1.1x+1.12y)−(1.1x+1.1y)=12760−12650(1.1x + 1.12y) - (1.1x + 1.1y) = 12760 - 12650

0.02y=1100.02y = 110

When we subtract, the 1.1x1.1x terms cancel out, leaving us with just the yy terms. This is a clever way to eliminate one variable quickly.


y=1100.02=5500y = \frac{110}{0.02} = 5500


Using the first equation:

x=11500−5500=6000x = 11500 - 5500 = 6000


Fiction books in 2015:

1.1×6000=66001.1 \times 6000 = 6600


There were 6600 fiction books in the library in 2015.

When dealing with percentage change problems, always convert percentages to decimals (10% increase = multiply by 1.1) and look for opportunities to eliminate variables by strategic multiplication and subtraction.

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