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1000 patients currently suffering from a disease were selected to study the effectiveness of treatment of four types of medicines A, B, C and D. These patients were first randomly assigned into two groups of equal size, called treatment group and control group. The patients in the control group were not treated with any of these medicines; instead they were given a dummy medicine, called placebo, containing only sugar and starch. The following information is known about the patients in the treatment group.

  1. A total of 250 patients were treated with type A medicine and a total of 210 patients were treated with type C medicine.
  2. 25 patients were treated with type A medicine only. 20 patients were treated with type C medicine only. 10 patients were treated with type D medicine only.
  3. 35 patients were treated with type A and type D medicines only. 20 patients were treated with type A and type B medicines only. 30 patients were treated with type A and type C medicines only. 20 patients were treated with type C and type D medicines only.
  4. 100 patients were treated with exactly three types of medicines.
  5. 40 patients were treated with medicines of types A, B and C, but not with medicines of type D. 20 patients were treated with medicines of types A, C and D, but not with medicines of type В.
  6. 50 patients were given all the four types of medicines. 75 patients were treated with exactly one type of medicine.

How many patients were treated with medicine type B?

Entered answer:

Solution

✅ Correct Answer: 340
Slide 1/13

Understanding the set :-

  1. This set tells us about four medicines - A, B , C, and D, which are tested on 1000 people.
  1. These patients were first randomly assigned into two groups of equal size, called treatment group and control group

a) Control group - patients in the control group were not treated with any of these medicines; instead they were given a dummy medicine, called placebo, containing only sugar and starch

This is a 4-Venn diagram set :

In this set we have 4 overlapping areas (A, B, C, D)

There will be some people who have taken 1 medicine among A, B, C, or D or any two or any three or all four.

we will try to find the exact numbers who belong to each category.

RegionValue
Only A
Only B
Only C
Only D
AB only
AC only
AD only
BC only
BD only
CD only
ABC only
ABD only
ACD only
BCD only
ABCD

Also,

TotalValue
Treatment Group500
Control Group500
Total A
Total C

We are given that,

These patients were first randomly assigned into two groups of equal size.

=> Treatment group = 500 people

and, Control group = 500 people

Also, The patients in the control group were not treated with any of these medicines

=> Only treatment group people have been administered with medicines, while the rest 500 have been given the placebo.

Based on the given information, we can then make the following table

RegionValue
Only A
Only B
Only C
Only D
AB only
AC only
AD only
BC only
BD only
CD only
ABC only
ABD only
ACD only
BCD only
ABCD

Also,

TotalValue
Treatment Group500
Control Group500
Total A250
Total C210

Clue 1 says,

i) A total of 250 patients were treated with type A medicine

ii) a total of 210 patients were treated with type C medicine.

We can directly add this in the diagram.

RegionValue
Only A25
Only B
Only C20
Only D10
AB only
AC only
AD only
BC only
BD only
CD only
ABC only
ABD only
ACD only
BCD only
ABCD

Also,

TotalValue
Treatment Group500
Control Group500
Total A250
Total C210

Clue 2,

i) 25 patients were treated with type A medicine only.

ii) 20 patients were treated with type C medicine only.

iii) 10 patients were treated with type D medicine only.

RegionValue
Only A25
Only B
Only C20
Only D10
AB only20
AC only30
AD only35
BC only
BD only
CD only20
ABC only
ABD only
ACD only
BCD only
ABCD

Also,

TotalValue
Treatment Group500
Control Group500
Total A250
Total C210

Clue 3 says,

i) 35 patients were treated with type A and type D medicines only.

ii) 20 patients were treated with type A and type B medicines only.

iii) 30 patients were treated with type A and type C medicines only.

iv) 20 patients were treated with type C and type D medicines only.

RegionValue
Only A25
Only B
Only C20
Only D10
AB only20
AC only30
AD only35
BC only
BD only
CD only20
ABC only
ABD only
ACD only
BCD only
ABCD

Also,

TotalValue
Treatment Group500
Control Group500
Total A250
Total C210

Clue 4 says,

100 patients were treated with exactly three types of medicines.

=> patients treated with -

(A + B + C) + (A + C + D) + (A + B + D) + (B + C + D) = 100

RegionValue
Only A25
Only B
Only C20
Only D10
AB only20
AC only30
AD only35
BC only
BD only
CD only20
ABC only40
ABD only
ACD only20
BCD only
ABCD

Also,

TotalValue
Treatment Group500
Control Group500
Total A250
Total C210

Clue 5 says,

i) 40 patients were treated with medicines of types A, B and C, but not with medicines of type D.

ii) 20 patients were treated with medicines of types A, C and D, but not with medicines of type B.

=> A + B + C = 40

and, A + C + D = 20

RegionValue
Only A25
Only B20
Only C20
Only D10
AB only20
AC only30
AD only35
BC only
BD only
CD only20
ABC only40
ABD only
ACD only20
BCD only
ABCD50

Also,

TotalValue
Treatment Group500
Control Group500
Total A250
Total C210

Clue 6 says,

i)50 patients were given all the four types of medicines.

ii) 75 patients were treated with exactly one type of medicine.

From clue 2 , we know

Only A = 25

Only c = 20

and, only D = 10

=> Only B = 75 - 25 - 20 - 10 = 20

RegionValue
Only A25
Only B20
Only C20
Only D10
AB only20
AC only30
AD only35
BC only
BD only
CD only20
ABC only40
ABD only30
ACD only20
BCD only10
ABCD50

Also,

TotalValue
Treatment Group500
Control Group500
Total A250
Total C210

Now, lets first take A,

We know total of A = 250

Also, we have all values of A except one, of A + B + D

Therefore, A + B + D = 250−(25−30−20−35−20−40−50)=30250 - (25 - 30 - 20 - 35 - 20 - 40 - 50) = 30

Now, from Clue 4 we know,

(A + B + C) + (A + C + D) + (A + B + D) + (B + C + D) = 100

Also, from clue 5 - A + B + C = 40

and, A + C + D = 20

And we have found out - A + B + D = 30

=> B + C + D = 100−(40+20+30)=10100 - (40 + 20 + 30) = 10

RegionValue
Only A25
Only B20
Only C20
Only D10
AB only20
AC only30
AD only35
BC only20
BD only
CD only20
ABC only40
ABD only30
ACD only20
BCD only10
ABCD50

Also,

TotalValue
Treatment Group500
Control Group500
Total A250
Total C210

Similarly, now,

we know total of C = 210

Also, we have all values except one, of B + C

Therefore, B + C = 210−(30−40−20−20−10−50−20)=20210 - (30 - 40 - 20 - 20 - 10 - 50 - 20) = 20

RegionValue
Only A25
Only B20
Only C20
Only D10
AB only20
AC only30
AD only35
BC only20
BD only150
CD only20
ABC only40
ABD only30
ACD only20
BCD only10
ABCD50

Also,

TotalValue
Treatment Group500
Control Group500
Total A250
Total C210

It is given to us that the total number of people whom medicines were assigned = 500

Now, we have all value except one

Firstly, let's take the total of all values -

= complete A + 20+20+10+20+20+10+20 + 20 + 10 + 20 + 20 + 10 + (B + D)

=> 250+20+20+10+20+20+10+250 + 20 + 20 + 10 + 20 + 20 + 10 + (B + D)

= 350350 + (B + D)

Now, we know total of whole = 500

=> 350350 + (B + D) = 500500

=> B + D = 150150

RegionValue
Only A25
Only B20
Only C20
Only D10
AB only20
AC only30
AD only35
BC only20
BD only150
CD only20
ABC only40
ABD only30
ACD only20
BCD only10
ABCD50

Also,

TotalValue
Treatment Group500
Control Group500
Total A250
Total C210

20+20+40+20+50+10+30+150=34020 + 20 + 40 + 20 + 50 + 10 + 30 + 150 = 340

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