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Let ana_n and bnb_n be two sequences such that an=13+6(n−1)a_n = 13 + 6 (n - 1) and bn=15+7(n−1)b_n = 15 + 7 (n - 1) for all natural numbers nn. Then, the largest three digit integer that is common to both these sequences, is

Entered answer:

Solution

✅ Correct Answer: 967

Let's start by understanding what these sequences actually look like.


For sequence an=13+6(n−1)a_n = 13 + 6(n-1):

a1=13+6(1−1)=13+0=13a_1 = 13 + 6(1-1) = 13 + 0 = 13

a2=13+6(2−1)=13+6=19a_2 = 13 + 6(2-1) = 13 + 6 = 19

a3=13+6(3−1)=13+12=25a_3 = 13 + 6(3-1) = 13 + 12 = 25

a4=13+6(4−1)=13+18=31a_4 = 13 + 6(4-1) = 13 + 18 = 31

So sequence ana_n: 13,19,25,31,37,43,49,55,61,67,73,79,85,...13, 19, 25, 31, 37, 43, 49, 55, 61, 67, 73, 79, 85, ...

For sequence bn=15+7(n−1)b_n = 15 + 7(n-1):

b1=15+7(1−1)=15+0=15b_1 = 15 + 7(1-1) = 15 + 0 = 15

b2=15+7(2−1)=15+7=22b_2 = 15 + 7(2-1) = 15 + 7 = 22

b3=15+7(3−1)=15+14=29b_3 = 15 + 7(3-1) = 15 + 14 = 29

b4=15+7(4−1)=15+21=36b_4 = 15 + 7(4-1) = 15 + 21 = 36

So sequence bnb_n: 15,22,29,36,43,50,57,64,71,78,85,...15, 22, 29, 36, 43, 50, 57, 64, 71, 78, 85, ...


We can spot the common terms: 43, 85, ...

Key Insight: Both sequences are arithmetic progressions (AP). When we want common terms between two APs, they form another AP!


The first common term is 43.

Why do we use LCM?

Sequence ana_n increases by 6 each time

Sequence bnb_n increases by 7 each time

The gap between consecutive common terms will be LCM(6,7) = 42

Think of it this way: Starting from 43, the next common term will be when both sequences "meet again." This happens after LCM(6,7) = 42 units.

Therefore, all common terms follow the pattern: 43,43+42,43+2×42,43+3×42,...43, 43+42, 43+2×42, 43+3×42, ...

General form: Common terms = 42k+4342k + 43 where k=0,1,2,3,...k = 0, 1, 2, 3, ...


We need the largest value of 42k+4342k + 43 that is still less than 1000.

42k+43<100042k + 43 < 1000

42k<95742k < 957

k<95742k < \tfrac{957}{42}

k<22.78...k < 22.78...

Since kk must be a whole number, the largest possible value is k=22k = 22.

Final Answer: 42(22)+43=924+43=96742(22) + 43 = 924 + 43 = 967

967

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