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Amal and Vimal together can complete a task in 150 days, while Vimal and Sunil together can complete the same task in 100 days. Amal starts working on the task and works for 75 days, then Vimal takes over and works for 135 days. Finally, Sunil takes over and completes the remaining task in 45 days. If Amal had started the task alone and worked on all days, Vimal had worked on every second day, and Sunil had worked on every third day, then the number of days required to complete the task would have been

Entered answer:

Solution

✅ Correct Answer: 139

We define variables for individual work rates. Let AA, VV, and SS represent the work rates of Amal, Vimal, and Sunil respectively (in units of work per day).

From the given information:

Amal + Vimal together: A+V=W150A + V = \frac{W}{150}

Vimal + Sunil together: V+S=W100V + S = \frac{W}{100}

We choose W=300W = 300 since it's divisible by both 150 and 100. This eliminates fractions and makes calculations easier.

With W=300W = 300:

A+V=300150=2A + V = \frac{300}{150} = 2 units per day

V+S=300100=3V + S = \frac{300}{100} = 3 units per day


From the actual work scenario:

75A+135V+45S=30075A + 135V + 45S = 300

We rewrite 135V135V as 75V+60V75V + 60V:

75A+75V+60V+45S=30075A + 75V + 60V + 45S = 300

Factor out 75: 75(A+V)+60V+45S=30075(A + V) + 60V + 45S = 300

Substituting A+V=2A + V = 2:

75(2)+60V+45S=30075(2) + 60V + 45S = 300

150+60V+45S=300150 + 60V + 45S = 300

60V+45S=15060V + 45S = 150

Rewrite as 45(V+S)+15V=15045(V + S) + 15V = 150


Substituting V+S=3V + S = 3:

45(3)+15V=15045(3) + 15V = 150

135+15V=150135 + 15V = 150

15V=1515V = 15

∴V=1∴ V = 1 unit per day

Finding others:

Since A+V=2A + V = 2 and V=1V = 1: A=1A = 1 unit per day

Since V+S=3V + S = 3 and V=1V = 1: S=2S = 2 units per day


Amal works every day (days 1, 2, 3, 4, 5, 6, ...)

Vimal works every 2nd day (days 2, 4, 6, 8, ...)

Sunil works every 3rd day (days 3, 6, 9, 12, ...)

Key insight: The pattern repeats every 6 days (LCM of 1, 2, and 3).


Day 1: Only A works = 1 unit

Day 2: A + V work = 1+1=21 + 1 = 2 units

Day 3: A + S work = 1+2=31 + 2 = 3 units

Day 4: A + V work = 1+1=21 + 1 = 2 units

Day 5: Only A works = 1 unit

Day 6: A + V + S work = 1+1+2=41 + 1 + 2 = 4 units

Total in 6 days = 1+2+3+2+1+4=131 + 2 + 3 + 2 + 1 + 4 = 13 units


We need 300 units total.

30013=23\frac{300}{13} = 23 complete cycles with remainder 1

Work done in 23 cycles = 23×13=29923 × 13 = 299 units

Days taken for 23 cycles = 23×6=13823 × 6 = 138 days

Remaining work = 300−299=1300 - 299 = 1 unit

On day 139 (day 1 of the new cycle), only Amal works and completes 1 unit.

Therefore, the total number of days required = 139 days

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