CATAlgebra > Medium63605457✅ Correct Option: 3Related questions:CAT 2024 Slot 2The sum of the infinite series is 15(15−17)+(15)2((15)2−(17)2)+(15)3((15)3−(17)3)+….\frac{1}{5}\left(\frac{1}{5}-\frac{1}{7}\right)+\left(\frac{1}{5}\right)^{2}\left(\left(\frac{1}{5}\right)^{2}-\left(\frac{1}{7}\right)^{2}\right)+\left(\frac{1}{5}\right)^{3}\left(\left(\frac{1}{5}\right)^{3}-\left(\frac{1}{7}\right)^{3}\right)+\ldots .51(51−71)+(51)2((51)2−(71)2)+(51)3((51)3−(71)3)+….. equal toCAT 2023 Slot 1For some positive and distinct real numbers x,yx, yx,y and zzz, if 1y+z\frac{1}{\sqrt{y}+\sqrt{z}}y+z1 is the arithmetic mean of 1x+z\frac{1}{\sqrt{x}+\sqrt{z}}x+z1 and 1x+y\frac{1}{\sqrt{x}+\sqrt{y}}x+y1, then the relationship which will always hold true, isCAT 2023 Slot 2Let both the series a1,a2,a3,…a_1, a_2, a_3, \dotsa1,a2,a3,… and b1,b2,b3…b_1, b_2, b_3 \dotsb1,b2,b3… be in arithmetic progression such that the common differences of both the series are prime numbers. If a5=b9a_5 = b_9a5=b9, a19=b19a_{19} = b_{19}a19=b19 and b2=0b_2 = 0b2=0, then a11a_{11}a11 equals