Skip to main contentSkip to solution

The equations 3x2−5x+p=03x^2 - 5x + p = 0 and 2x2−2x+q=02x^2 - 2x + q = 0 have one common root. The sum of the other roots of these two equations is

Solution

✅ Correct Option: 3

Let the common root be α\alpha.

Let β\beta be the other root of 3x2−5x+p=03x^2 - 5x + p = 0.

Let γ\gamma be the other root of 2x2−2x+q=02x^2 - 2x + q = 0.


Using sum of roots:

α+β=53  ⟹  β=53−α\alpha + \beta = \dfrac{5}{3} \implies \beta = \dfrac{5}{3} - \alpha

α+γ=22=1  ⟹  γ=1−α\alpha + \gamma = \dfrac{2}{2} = 1 \implies \gamma = 1 - \alpha

β+γ=53−α+1−α\beta + \gamma = \dfrac{5}{3} - \alpha + 1 - \alpha

=83−2α⋯(∗)= \dfrac{8}{3} - 2\alpha \quad \cdots (*)


Since α\alpha satisfies both equations:

3α2−5α+p=0  ⟹  p=5α−3α2⋯(1)3\alpha^2 - 5\alpha + p = 0 \implies p = 5\alpha - 3\alpha^2 \quad \cdots (1)

2α2−2α+q=0  ⟹  q=2α−2α2⋯(2)2\alpha^2 - 2\alpha + q = 0 \implies q = 2\alpha - 2\alpha^2 \quad \cdots (2)


Now, 83−p+32q\dfrac{8}{3} - p + \dfrac{3}{2}q

=83−(5α−3α2)+32(2α−2α2)= \dfrac{8}{3} - (5\alpha - 3\alpha^2) + \dfrac{3}{2}(2\alpha - 2\alpha^2)

=83−5α+3α2+3α−3α2= \dfrac{8}{3} - 5\alpha + 3\alpha^2 + 3\alpha - 3\alpha^2

=83−2α= \dfrac{8}{3} - 2\alpha

This matches (∗)(*).


Therefore, the sum of the other roots =83−p+32q= \dfrac{8}{3} - p + \dfrac{3}{2}q

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question