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Points AA and BB are 150 km150 \mathrm{~km} apart. Cars 11 and 22 travel from AA to BB, but car 22 starts from AA when car 11 is already 20 km20 \mathrm{~km} away from AA. Each car travels at a speed of 100kmph100 \mathrm{kmph} for the first 50 km50 \mathrm{~km}, at 50kmph50 \mathrm{kmph} for the next 50 km50 \mathrm{~km}, and at 25kmph25 \mathrm{kmph} for the last 50 km50 \mathrm{~km}. The distance, in km, between car 22 and BB when car 11 reaches BB is

Entered answer:

Solution

✅ Correct Answer: 5

Understanding the Problem Setup

Points A and B are 150 km apart. Both cars follow the same speed pattern:

First 50 km at 100 kmph

Next 50 km at 50 kmph

Last 50 km at 25 kmph

The key difference: Car 2 starts when Car 1 is already 20 km away from A.


Find the Time Head Start

When Car 1 has traveled 20 km, Car 2 starts its journey.

Since Car 1 travels the first 50 km at 100 kmph:

Time to travel 20 km =DistanceSpeed=20100=0.2= \frac{\text{Distance}}{\text{Speed}} = \frac{20}{100} = 0.2 hours =12= 12 minutes

So Car 1 has a 12-minute head start over Car 2.


Calculate Total Time for Car 1 to Reach B

Car 1's journey breakdown:

First 50 km at 100 kmph: Time =50100=0.5= \frac{50}{100} = 0.5 hours

Next 50 km at 50 kmph: Time =5050=1= \frac{50}{50} = 1 hour

Last 50 km at 25 kmph: Time =5025=2= \frac{50}{25} = 2 hours

Total time for Car 1 =0.5+1+2=3.5= 0.5 + 1 + 2 = 3.5 hours


Find Car 2's Travel Time When Car 1 Reaches B

Since Car 2 started 12 minutes (0.2 hours) later:

Car 2's travel time =3.5−0.2=3.3= 3.5 - 0.2 = 3.3 hours


Calculate How Far Car 2 Travels in 3.3 Hours

Car 2's journey in 3.3 hours:

First 50 km at 100 kmph: Takes 0.5 hours

Next 50 km at 50 kmph: Takes 1 hour

Remaining time =3.3−0.5−1=1.8= 3.3 - 0.5 - 1 = 1.8 hours

In the last segment (25 kmph zone), Car 2 travels for 1.8 hours:

Distance covered =Speed×Time=25×1.8=45= \text{Speed} \times \text{Time} = 25 \times 1.8 = 45 km

Total distance covered by Car 2 =50+50+45=145= 50 + 50 + 45 = 145 km


Find Distance Between Car 2 and B

Distance between Car 2 and B =Total distance−Distance covered by Car 2= \text{Total distance} - \text{Distance covered by Car 2}

=150−145=5= 150 - 145 = 5 km


Since both cars follow identical speed patterns, the time difference between them remains constant throughout their journey. Car 1's 12-minute head start means Car 2 will always be 12 minutes behind, which translates to being 5 km away from B when Car 1 reaches B.

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