CATAlgebra > EasyEntered answer:✅ Correct Answer: 20Related questions:CAT 2020 Slot 1Among 100100100 students, x1x_{1}x1 have birthdays in January, x2x_{2}x2 have birthday in February, and so on. If x0=max(x1,x2,…,x12)x_{0}=\max \left(x_{1}, x_{2}, \ldots , x_{12}\right)x0=max(x1,x2,…,x12), then the smallest possible value of x0x_{0}x0 isCAT 2020 Slot 2If xxx and yyy are positive real numbers satisfying x+y=102x + y = 102x+y=102, then the minimum possible value of 2601(1+1x)(1+1y)2601(1+\frac{1}{x})(1+\frac{1}{y})2601(1+x1)(1+y1) isCAT 2018 Slot 2Let a1,a2,…,a52a_{1}, a_{2}, \ldots, a_{52}a1,a2,…,a52 be positive integers such that a1<a2<…<a52a_{1}<a_{2}<\ldots<a_{52}a1<a2<…<a52. Suppose, their arithmetic mean is one less than the arithmetic mean of a2,a3a_{2}, a_{3}a2,a3, …,a52\ldots, a_{52}…,a52. If a52=100a_{52}=100a52=100, then the largest possible value of a1a_{1}a1 is