CATAlgebra > Medium202020232323454545484848✅ Correct Option: 2Related questions:CAT 2020 Slot 2If xxx and yyy are positive real numbers satisfying x+y=102x + y = 102x+y=102, then the minimum possible value of 2601(1+1x)(1+1y)2601(1+\frac{1}{x})(1+\frac{1}{y})2601(1+x1)(1+y1) isCAT 2019 Slot 2What is the largest positive integer such that n2+7n+12n2−n−12\frac{n^2 + 7n + 12}{n^2 - n - 12}n2−n−12n2+7n+12 is also a positive integer?CAT 2018 Slot 1Let f(x)=f(x) =f(x)= min{2x2,52−5x2x², 52-5x2x2,52−5x}, where x is any positive real number. Then the maximum possible value of f(x)f(x)f(x) is