Three men and eight machines can finish a job in half the time taken by three machines and eight men to finish the same job. If two machines can finish the job in days, then how many men can finish the job in days?
Three men and eight machines can finish a job in half the time taken by three machines and eight men to finish the same job. If two machines can finish the job in days, then how many men can finish the job in days?
Entered answer:
Solution
We need to find how many men can finish a job in 13 days, given:
3 men + 8 machines finish a job in half the time of 8 men + 3 machines
2 machines can finish the job in 13 days
Let's define:
M = work rate of 1 man (portion of job completed per day)
Mc = work rate of 1 machine (portion of job completed per day)
Work rate × Time = Total work completed
3 men + 8 machines take half the time of 8 men + 3 machines
This means:
Time for (3 men + 8 machines) = t days
Time for (8 men + 3 machines) = 2t days
Since both combinations complete the same job:
(3M + 8Mc) × t = (8M + 3Mc) × 2t
Since both sides equal the total work (1 unit):
(3M + 8Mc) × t = 1
(8M + 3Mc) × 2t = 1
From the first equation: t =
From the second equation: 2t =
Therefore: t =
Setting our two expressions for t equal:
Cross-multiplying:
2(8M + 3Mc) = 3M + 8Mc
16M + 6Mc = 3M + 8Mc
13M = 2Mc
Therefore: 1 Machine = Men = 6.5 Men
2 machines can finish the job in 13 days
This means: 2Mc × 13 = 1 (complete job)
So: Mc = (1 machine completes of the job per day)
Since 1 machine = 6.5 men:
2 machines = 2 × 6.5 = 13 men
If 2 machines can finish the job in 13 days, then 13 men can also finish the job in 13 days.
13 men can finish the job in 13 days.