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The rate of water flow through three pipes A, B and C are in the ratio 4 : 9 : 36. An empty tank can be filled up completely by pipe A in 15 hours. If all the three pipes are used simultaneously to fill up this empty tank, the time, in minutes, required to fill up the entire tank completely is nearest to

Solution

✅ Correct Option: 3

The flow rates of pipes A, B and C are in the ratio 4:9:364 : 9 : 36, and pipe A alone fills the tank in 1515 hours.


Since pipe A fills the tank in 1515 hours, its rate is

115\dfrac{1}{15} tank per hour

Pipe A corresponds to 44 parts in the ratio, so

4 parts=1154 \text{ parts} = \dfrac{1}{15}

1 part=1601 \text{ part} = \dfrac{1}{60}

Using this, we get the individual rates:

PipeRatio PartsRate (tank/hour)
A4460\dfrac{4}{60}
B9960\dfrac{9}{60}
C363660\dfrac{36}{60}

When all three pipes work together, their rates add up:

Combined Rate=460+960+3660=4960\text{Combined Rate} = \dfrac{4}{60} + \dfrac{9}{60} + \dfrac{36}{60} = \dfrac{49}{60} tank per hour


Time to fill the tank is the reciprocal of the combined rate (since Time =1Rate= \dfrac{1}{\text{Rate}}):

Time=14960=6049\text{Time} = \dfrac{1}{\frac{49}{60}} = \dfrac{60}{49} hours


Converting to minutes:

6049×60=360049≈73.47\dfrac{60}{49} \times 60 = \dfrac{3600}{49} \approx 73.47 minutes

≈73 minutes\boxed{\approx 73 \text{ minutes}}


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