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Ankita walks from A to C through B, and runs back through the same route at a speed that is 40% more than her walking speed. She takes exactly 3 hours 30 minutes to walk from B to C as well as to run from B to A. The total time, in minutes, she would take to walk from A to B and run from B to C, is

Entered answer:

Solution

✅ Correct Answer: 444

Let walking speed =w= w and running speed =1.4w= 1.4w (since running is 40% faster).

Let distance from A to B =d1= d_1 and distance from B to C =d2= d_2.


Time to walk from B to C =3= 3 hours 3030 minutes =3.5= 3.5 hours:

d2w=3.5\dfrac{d_2}{w} = 3.5

d2=3.5wd_2 = 3.5w


Time to run from B to A =3= 3 hours 3030 minutes =3.5= 3.5 hours:

d11.4w=3.5\dfrac{d_1}{1.4w} = 3.5

d1=3.5×1.4wd_1 = 3.5 \times 1.4w

d1=4.9wd_1 = 4.9w


Total time to walk from A to B and run from B to C:

=d1w+d21.4w= \dfrac{d_1}{w} + \dfrac{d_2}{1.4w}

=4.9ww+3.5w1.4w= \dfrac{4.9w}{w} + \dfrac{3.5w}{1.4w}

=4.9+2.5= 4.9 + 2.5

=7.4= 7.4 hours


Converting to minutes:

7.4×60=4447.4 \times 60 = 444 minutes

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