CATAlgebra > Medium(−∞,18]∪[1,∞)\left(-\infty,\frac{1}{8}\right]\cup[1,\infty)(−∞,81]∪[1,∞)(−∞,18]∪[12,∞)\left(-\infty,\frac{1}{8}\right]\cup\left[\frac{1}{2},\infty\right)(−∞,81]∪[21,∞)(−∞,14]∪[1,∞)\left(-\infty,\frac{1}{4}\right]\cup[1,\infty)(−∞,41]∪[1,∞)(−∞,14]∪[12,∞)\left(-\infty,\frac{1}{4}\right]\cup\left[\frac{1}{2},\infty\right)(−∞,41]∪[21,∞)✅ Correct Option: 2Related questions:CAT 2020 Slot 3If f(x+y)=f(x)f(y)f(x + y) = f (x) f (y)f(x+y)=f(x)f(y) and f(5)=4f(5) = 4f(5)=4, then f(10)−f(−10)f (10) - f (-10)f(10)−f(−10) is equal to2025 Slot 2Let f(x)=x(2x−1)f(x) = \dfrac{x}{(2x-1)}f(x)=(2x−1)x and g(x)=x(x−1)g(x) = \dfrac{x}{(x-1)}g(x)=(x−1)x. Then, the domain of the function h(x)=f(g(x))+g(f(x))h(x) = f(g(x)) + g(f(x))h(x)=f(g(x))+g(f(x)) is all real numbers exceptCAT 2024 Slot 3For any non-zero real number x, let f(x)+2f(1x)=3xf(x) + 2 f(\frac{1}{x}) = 3xf(x)+2f(x1)=3x. Then, the sum of all possible values of xxx for which f(x)=3f(x) = 3f(x)=3, is