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Arun, Varun and Tarun, if working alone, can complete a task in 24, 21, and 15 days, respectively. They charge Rs 2160, Rs 2400, and Rs 2160 per day, respectively, even if they are employed for a partial day. On any given day, any of the workers may or may not be employed to work. If the task needs to be completed in 10 days or less, then the minimum possible amount, in rupees, required to be paid for the entire task is

Solution

✅ Correct Option: 1

Work done per day by each worker:

Arun =124= \dfrac{1}{24}

Varun =121= \dfrac{1}{21}

Tarun =115= \dfrac{1}{15}


To minimize cost, find the cost each worker would charge to complete the entire task alone:

Arun =2160×24== 2160 \times 24 = Rs 51,84051,840

Varun =2400×21== 2400 \times 21 = Rs 50,40050,400

Tarun =2160×15== 2160 \times 15 = Rs 32,40032,400

So Tarun is the cheapest per unit of work, followed by Varun, then Arun.


To minimize cost, employ Tarun for the maximum allowed 10 days:

Work done by Tarun in 10 days =1015=23= \dfrac{10}{15} = \dfrac{2}{3}

Remaining work =1−23=13= 1 - \dfrac{2}{3} = \dfrac{1}{3}


The next cheapest worker is Varun. Days Varun needs for the remaining 13\dfrac{1}{3} work:

=1/31/21= \dfrac{1/3}{1/21}

=213= \dfrac{21}{3}

=7= 7 days

This is within the 10-day limit, since Varun works alongside Tarun on 7 of those 10 days.


Tarun's pay =10×2160== 10 \times 2160 = Rs 21,60021,600

Varun's pay =7×2400== 7 \times 2400 = Rs 16,80016,800

Total =21,600+16,800== 21,600 + 16,800 = Rs 38,40038,400


Note: Using Arun instead of Varun for the remaining 13\dfrac{1}{3} work would require 1/31/24=8\dfrac{1/3}{1/24} = 8 days, costing 8×2160=8 \times 2160 = Rs 17,28017,280, which is more than Varun's Rs 16,80016,800. Also, workers charge a full day's wage even for partial days, so only full days of work are optimal.


The minimum possible amount required is Rs 38,40038,400.

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