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The number of distinct pairs of integers (x,y)(x, y) satisfying the inequalities x>y≥3x > y \geq 3 and x+y<14x + y < 14 is

Entered answer:

Solution

✅ Correct Answer: 16

The three conditions are: x>yx > y, y≥3y \geq 3, and x+y<14x + y < 14.

For any fixed yy, the valid range for xx is: y<x<14−yy < x < 14 - y


When y=3y = 3: xx ranges from 44 to 1010, so x∈{4,5,6,7,8,9,10}x \in \{4, 5, 6, 7, 8, 9, 10\} — 7 pairs

When y=4y = 4: xx ranges from 55 to 99, so x∈{5,6,7,8,9}x \in \{5, 6, 7, 8, 9\} — 5 pairs

When y=5y = 5: xx ranges from 66 to 88, so x∈{6,7,8}x \in \{6, 7, 8\} — 3 pairs

When y=6y = 6: xx ranges from 77 to 77, so x∈{7}x \in \{7\} — 1 pair

When y=7y = 7: x>7x > 7 and x<7x < 7 is impossible — 0 pairs

For y≥7y \geq 7, no valid xx exists, so we stop here.


Total pairs =7+5+3+1=16= 7 + 5 + 3 + 1 = 16

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