CATAlgebra > Hard−2-2−2666222−4-4−4✅ Correct Option: 1Related questions:CAT 2019 Slot 1If a1,a2….a_{1}, a_{2} \ldots .a1,a2….. are in A.P., then, 1a1+a2+1a2+a3+….+1an+an+1\frac{1}{\sqrt{a_{1}}+\sqrt{a_{2}}}+\frac{1}{\sqrt{a_{2}}+\sqrt{a_{3}}}+\ldots .+\frac{1}{\sqrt{a_{n}}+\sqrt{a_{n+1}}}a1+a21+a2+a31+….+an+an+11 is equal toCAT 2021 Slot 1The natural numbers are divided into groups as (1), (2,3,4),(5,6,7,8,9),….(2,3,4),(5,6,7,8,9), \ldots .(2,3,4),(5,6,7,8,9),….. and so on. Then, the sum of the numbers in the 15th group is equal toCAT 2024 Slot 2The sum of the infinite series is 15(15−17)+(15)2((15)2−(17)2)+(15)3((15)3−(17)3)+….\frac{1}{5}\left(\frac{1}{5}-\frac{1}{7}\right)+\left(\frac{1}{5}\right)^{2}\left(\left(\frac{1}{5}\right)^{2}-\left(\frac{1}{7}\right)^{2}\right)+\left(\frac{1}{5}\right)^{3}\left(\left(\frac{1}{5}\right)^{3}-\left(\frac{1}{7}\right)^{3}\right)+\ldots .51(51−71)+(51)2((51)2−(71)2)+(51)3((51)3−(71)3)+….. equal to