Dick is thrice as old as Tom and Harry is twice as old as Dick. If Dick's age is year less than the average age of all three, then Harry's age, in years, is
Dick is thrice as old as Tom and Harry is twice as old as Dick. If Dick's age is year less than the average age of all three, then Harry's age, in years, is
Entered answer:
Solution
✅ Correct Answer: 18
We need to set up equations based on the age relationships given.
Let Tom's age = x years
From the problem:
Dick is thrice as old as Tom → Dick's age = 3x years
Harry is twice as old as Dick → Harry's age = 2 × (Dick's age) = 2 × 3x = 6x years
The average age of all three people is:
The problem states: "Dick's age is 1 year less than the average age of all three"
This means: Dick's age = Average age - 1
Multiply everything by 3 to eliminate the fraction:
Since x = 3 and Harry's age = 6x:
Therefore, Harry's age is 18 years.