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Vimla starts for office every day at 99 am and reaches exactly on time if she drives at her usual speed of 40 km/hr40 \mathrm{~km} / \mathrm{hr}. She is late by 66 minutes if she drives at 35 km/hr35 \mathrm{~km} / \mathrm{hr}. One day, she covers two-thirds of her distance to office in onethirds of her usual time to reach office, and then stops for 88 minutes. The speed, in km/hr, at which she should drive the remaining distance to reach office exactly on time is

Solution

✅ Correct Option: 2

When Vimla drives at different speeds, the distance to office remains the same - only the time changes.

Let's say her usual time to reach office is t minutes.

At usual speed: Distance = 40 × t km

At slower speed: Distance = 35 × (t + 6) km

Since the distance is the same in both cases:

40t=35(t+6)40t = 35(t + 6)


40t=35t+21040t = 35t + 210

40t−35t=21040t - 35t = 210

5t=2105t = 210

t=42t = 42 minutes

We're using the fact that Distance = Speed × Time, and since distance is constant, we can equate the two expressions.


Distance = Speed × Time = 40 × 42 minutes

Converting to hours: 42 minutes = 4260\frac{42}{60} hours = 710\frac{7}{10} hours

Distance = 40 × 710\frac{7}{10} = 28 km


On this day, Vimla covers:

Distance covered: 23\frac{2}{3} of total distance = 23\frac{2}{3} × 28 = 563\frac{56}{3} km

Time taken: 13\frac{1}{3} of usual time = 13\frac{1}{3} × 42 = 14 minutes

Stop time: 8 minutes


Time already used = 14 minutes (driving) + 8 minutes (stop) = 22 minutes

Time remaining to reach on time = 42 - 22 = 20 minutes


Distance remaining = Total distance - Distance already covered

= 28 - 563\frac{56}{3}

= 843\frac{84}{3} - 563\frac{56}{3}

= 283\frac{28}{3} km

Time available = 20 minutes = 2060\frac{20}{60} hours = 13\frac{1}{3} hour

Required speed = Distance ÷ Time = 283\frac{28}{3} ÷ 13\frac{1}{3} = 283\frac{28}{3} × 31\frac{3}{1} = 28 km/hr


We need to drive at 28 km/hr for the remaining distance.

In speed-time problems, always remember that when the distance is constant, we can set up equations using Speed₁ × Time₁ = Speed₂ × Time₂.

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