Skip to main contentSkip to solution

Eight gymnastics players numbered 1 through 8 underwent a training camp where they were coached by three coaches - Xena, Yuki, and Zara. Each coach trained at least two players. Yuki trained only even numbered players, while Zara trained only odd numbered players. After the camp, the coaches evaluated the players and gave integer ratings to the respective players trained by them on a scale of 1 to 7, with 1 being the lowest rating and 7 the highest.

The following additional information is known.

  1. Xena trained more players than Yuki.
  2. Player-1 and Player-4 were trained by the same coach, while the coaches who trained Player-2, Player-3 and Player-5 were all different.
  3. Player-5 and Player-7 were trained by the same coach and got the same rating. All other players got a unique rating.
  4. The average of the ratings of all the players was 4.
  5. Player-2 got the highest rating.
  6. The average of the ratings of the players trained by Yuki was twice that of the players trained by Xena and two more than that of the players trained by Zara.
  7. Player-4's rating was double of Player-8's and less than Player-5's.

Who all were the players trained by Xena?

Solution

✅ Correct Option: 3
Slide 1/10

In the set we are given that each coach had atleast 2 players.

So, there are only two possibilities:- 3+3+2=8 or 4+2+2=8.

Also, According to clue 1,

Xena has trained more players than Yuki

therefore two cases can be made as follows -

XenaYukiZara
323
422
PlayerXENAYUKI
ZARA
Rating
Player 1x
Player 2x
Player 3x
Player 4x
Player 5x
Player 6x
Player 7x
Player 8x

To fill this table we will need to find the coach who had trained a particular player and the rating given by him.

Also, we know from the question, that

Yuki trained only Even numbered players

and Zara trained only odd numbered players.

PlayerXENAYUKI
ZARA
Rating
Player 1✓xx
Player 2x✓x
Player 3x
Player 4✓xx
Player 5x
Player 6x
Player 7x
Player 8x

Using clue 2 -

Player 1 and player 4 was trained by same coach, which can only be Xena.

Also, The coaches who trained Player-2, Player-3 and Player-5 are all different.

But player 3 and player 5 can't be trained by Yuki

hence, player 2 must be trained by yuki.

PlayerXENAYUKI
ZARA
Rating
Player 1✓xx
Player 2x✓x
Player 3✓xx
Player 4✓xx
Player 5xx✓
Player 6x
Player 7xx✓
Player 8x

Now using Clue 3 ,

We know player 5 and player 7 was trained by same coach.

But, we already know that Player 3 and Player 5 cannot be trained by the same Person.

If for example, player 5 and 7 were trained by Xena then player 3 will be trained by Zara,

but it will contradict first clue that all the coaches had trained atleast 2 players.

Therefore, only possiblity is player 5 and 7 are trianed by Zara and player 3 then will be trained by Xena.

Therefore, the number of players trained by the coaches are fixed.

Xena - 4

Yuki - 2

Zara - 2

PlayerXENAYUKI
ZARA
Rating
Player 1✓xx
Player 2x✓x
Player 3✓xx
Player 4✓xx
Player 5xx✓4
Player 6x
Player 7xx✓4
Player 8x

As given in clue 3 &4 ,

Player 5 and Player 7 got trained by the same coach and both got the same ratings. All other players got a unique rating.

And, The average of the ratings of all the players is 4. Total ratings is 8*4 = 32.

The sum of ratings will be 1 + 2 + 3 + 4 + 5 + 6 + 7 + x = 32.

Therefore x = 4.

Therefore Player 5 and Player 7 got a rating of 4.

PlayerXENAYUKI
ZARA
Rating
Player 1✓xx
Player 2x✓x7
Player 3✓xx
Player 4✓xx2
Player 5xx✓4
Player 6x
Player 7xx✓4
Player 8x1

Now, using clue 5,

Player 2 got the highest rating which is 7.

Also clue 7 says, Player 4 rating was double of Player 8 and less than Player 5.

Player 4 should get an even number rating less than 4 which is 2.

Player 4 rating is 2 and Player 8 rating is 1.

PlayerXENAYUKI
ZARA
Rating
Player 1✓xx
Player 2x✓x7
Player 3✓xx
Player 4✓xx2
Player 5xx✓4
Player 6x
Player 7xx✓4
Player 8x1

Using clue 6,

The average of the ratings of the players trained by Yuki was twice that of the players trained by Xena, and two more than that of the players trained by Zara.

We know that players trained by zara are 5 and 7 who has a rating of 4 each.

Therefore, average of ratings given by Zara will be 4.

So, average of rating given by Yuki = 4 + 2 = 6

similarly, Average of ratings given by Xena = 6/2 = 3.

PlayerXENAYUKI
ZARA
Rating
Player 1✓xx
Player 2x✓x7
Player 3✓xx
Player 4✓xx2
Player 5xx✓4
Player 6x✓x5
Player 7xx✓4
Player 8✓xx1

We know, Average of ratings given by Yuki to two players is 6 and One of them is Player 2 whose rating is 7.

Therefore, the other player should have got rating 5.

which has to be of one among player 6 or 8.

But player 8 rating is 1,

Hence Player 6’s rating is 5.

Since Player 6 is trained by Yuki, Player 8 has to be trainer by Xena.

PlayerXENAYUKI
ZARA
Rating
Player 1✓xx6/3
Player 2x✓x7
Player 3✓xx3/6
Player 4✓xx2
Player 5xx✓4
Player 6x✓x5
Player 7xx✓4
Player 8✓xx1

Here, we can't determine the exact value of rating given to player 1 and player 3 but can conclude that it will be one among 3 or 6.

In DILR sets many times you will find more than one cases, but that's completely alright, the questions of the set will give you more details, if needed.

The final table will be as follows:-

PlayerXENAYUKI
ZARA
Rating
Player 1✓xx6/3
Player 2x✓x7
Player 3✓xx3/6
Player 4✓xx2
Player 5xx✓4
Player 6x✓x5
Player 7xx✓4
Player 8✓xx1

Xena has trained player 1, 3,4,and 8.

Hence option C

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question