Solution
✅ Correct Option: 1
Firstly, let's calculate the length of the paths in this question:-
KN = ML = 400m
and. ON = 300m
Using phythagorus theorum,
KO = 500m
Similairly,
HJ = OP = 150m
GJ = EL = 200m
HG = 250m
The shortest path is L-K-O-P-I-G-B-C-F-E-L.
Hence the minimum distance is LK+KO+OP+PI+IG+GB+BC+CF+FE+EL=
300+500+150+400+250+400+300+400+300+200= 3200 m.