Solution
Firstly, let's understand what the set says:
- There are two ways to operate the AC - regular and power.
- There is a set temperature of the AC. It is a temperature that the AC will automatically reach when it is off.
- Regular mode of the AC brings down the temperature inside the room (called inside temperature) at a constant rate to the set temperature in 1 hour.
- Power mode of the AC brings down the temperature inside the room (called inside temperature) at a constant rate to the set temperature in 30 minutes.
- When the AC is turned off, the temperature rises linearly, reaching the temperature at the time it was turned off in one hour.
- The temperature outside has been falling at a constant rate from 7 pm onward until 3 am on a particular night.
- The graph in the question describes the inside temperature of the room every 30 minutes starting from 23:00.
| Time | Temperature | AC - on / off |
|---|---|---|
| 23:00 | 38 | on |
| 23:30 | 32 | on |
| 00:00 | 26 | off |
| 00:30 | 31 | on |
| 01:00 | 26 | off |
| 01:30 | 30 | on |
| 02:00 | 28 |
This is the table we can directly make from the graph.
Now, we will first try to find out when the AC was on or off.
From 23:00 to 23:30, the temperature decreased, which means the AC was on.
From 23:30 to 00:00, the temperature decreased, which means the AC was on.
From 00:00 to 00:30, the temperature increased, which means the AC was off.
From 00:30 to 01:00, the temperature decreased, which means the AC was on.
From 01:00 to 01:30, the temperature increased, which means the AC was off.
From 01:30 to 02:00, the temperature decreased, which means the AC was on.
| Time | Temperature | AC - on / off |
|---|---|---|
| 23:00 | 38 | on |
| 23:30 | 32 | on |
| 00:00 | 26 | off |
| 00:30 | 31 | on |
| 01:00 | 26 | off |
| 01:30 | 30 | on |
| 02:00 | 28 |
From the given information,
We know the AC was started for the first time at 23:00.
This simply means that before the AC was turned on, the room temperature was the same as the outside temperature. Therefore, the temperature at 23:00 (which is 38 degrees) is the outside temperature at that time.
| Time | Temperature | AC - on / off | Outside temperature |
|---|---|---|---|
| 23:00 | 38 | on | 38 |
| 23:30 | 32 | on | |
| 00:00 | 26 | off | 36 |
| 00:30 | 31 | on | |
| 01:00 | 26 | off | |
| 01:30 | 30 | on | |
| 02:00 | 28 |
We know from the table that the AC was turned off at 00:00.
According to the question, when the AC is off, the room temperature must reach the outside temperature in 1 hour.
The temperature rises from 26 degrees to 31 degrees at 00:30 (an increase of 5 degrees in 30 minutes).
Since the temperature rises at a constant rate, this means there would be an increase of 10 degrees in 1 hour (5 degrees × 2 = 10 degrees).
Therefore, the outside temperature at 00:00 was 26 + 10 = 36 degrees.
| Time | Temperature | AC - on / off | Outside temperature |
|---|---|---|---|
| 23:00 | 38 | on | 38 |
| 23:30 | 32 | on | 37 |
| 00:00 | 26 | off | 36 |
| 00:30 | 31 | on | 35 |
| 01:00 | 26 | off | 34 |
| 01:30 | 30 | on | 33 |
| 02:00 | 28 | 32 |
We also know that the outside temperature has decreased at a constant rate.
We found that it was 38 degrees at 23:00 and 36 degrees at 00:00.
This means the temperature decreased by 2 degrees in 1 hour (60 minutes). Since the rate is constant, this equals 1 degree every 30 minutes.
Since the temperature decreases at a constant rate, at 23:30 it will be 37 degrees.
From this, we can now find the rate at which the outside temperature has decreased, which is 1 degree every 30 minutes.
| Time | Temperature | AC - On / Off | Outside temperature |
|---|---|---|---|
| 23:00 | 38 | ON | 38 |
| 23:30 | 32 | ON | 37 |
| 00:00 | 26 | OFF | 36 |
| 00:30 | 31 | ON | 35 |
| 01:00 | 26 | OFF | 34 |
| 01:30 | 30 | ON | 33 |
| 02:00 | 28 | 32 |
We know that the AC got turned ON after 11:01 PM at 12:30 AM and 1:30 AM.
Hence, the answer is 'Exactly 3'