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For a sequence of real numbers x1,x2,......xnx_1, x_2, ...... x_n, if x1−x2+x3−....+(−1)n+1xn=n2+2nx_1 - x_2 + x_3 - .... + (-1)^{n + 1} x_n = n^2 + 2n for all natural numbers n, then the sum x49+x50x_{49} + x_{50} equals

Solution

✅ Correct Option: 2

We have: x1−x2+x3−x4+⋯+(−1)n+1xn=n2+2nx_1 - x_2 + x_3 - x_4 + \cdots + (-1)^{n+1}x_n = n^2 + 2n

This equation tells us the alternating sum of the first n terms equals n2+2nn^2 + 2n.

Let's find individual terms by substituting small values of n:


For n=1n = 1:

x1=12+2(1)=3x_1 = 1^2 + 2(1) = 3


For n=2n = 2:

x1−x2=22+2(2)=8x_1 - x_2 = 2^2 + 2(2) = 8

Since x1=3x_1 = 3: 3−x2=83 - x_2 = 8

Therefore: x2=−5x_2 = -5


For n=3n = 3:

x1−x2+x3=32+2(3)=15x_1 - x_2 + x_3 = 3^2 + 2(3) = 15

Substituting: 3−(−5)+x3=153 - (-5) + x_3 = 15

8+x3=158 + x_3 = 15

Therefore: x3=7x_3 = 7


For n=4n = 4:

x1−x2+x3−x4=42+2(4)=24x_1 - x_2 + x_3 - x_4 = 4^2 + 2(4) = 24

Substituting: 3+5+7−x4=243 + 5 + 7 - x_4 = 24

15−x4=2415 - x_4 = 24

Therefore: x4=−9x_4 = -9


Now checking consecutive pairs:

x1+x2=3+(−5)=−2x_1 + x_2 = 3 + (-5) = -2

x3+x4=7+(−9)=−2x_3 + x_4 = 7 + (-9) = -2

Pattern: Each pair of consecutive terms sums to −2-2.


Since 4949 and 5050 are consecutive terms:

x49+x50=−2x_{49} + x_{50} = -2

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