CATAlgebra > Hardx≤rx \le rx≤rx≥rx \ge rx≥rx≠rx \ne rx=rx>rx > rx>r✅ Correct Option: 1Related questions:CAT 2019 Slot 1Consider a function fff satisfying f(x+y)=f(x)f(y)f(\mathrm{x}+\mathrm{y})=f(\mathrm{x}) \mathrm{f}(\mathrm{y})f(x+y)=f(x)f(y) where x,yx , yx,y are positive integers, and f(1)=2f(1)=2f(1)=2. If f(a+1)+f(a+2)+……+f(a+n)=f(\mathrm{a}+1)+f(\mathrm{a}+2)+\ldots \ldots+f(\mathrm{a}+\mathrm{n})=f(a+1)+f(a+2)+……+f(a+n)= 16(2n−1)16\left(2^{n}-1\right)16(2n−1) then a is equal toCAT 2019 Slot 1For any positive integer nnn, let f(n)=n(n+1)f(n)=n(n+1)f(n)=n(n+1) if nnn is even, and f(n)=n+3f(n)=n+3f(n)=n+3 if nnn is odd. If mmm is a positive integer such that 8f(m+1)−f(m)=28 f(m+1)-f(m)=28f(m+1)−f(m)=2, then mmm equalsCAT 2017 Slot 2Let f(x)=x2f(x) = x^2f(x)=x2 and g(x)=2xg(x) = 2^xg(x)=2x, for all real xxx. Then the value of f(f(g(x))+g(f(x)))f(f(g(x)) + g(f(x)))f(f(g(x))+g(f(x))) at x=1x = 1x=1 is