CATAlgebra > Hard494949494949485048504850495049504950484948494849✅ Correct Option: 2Related questions:CAT 2024 Slot 3Consider the sequence t1=1t_1 = 1t1=1, t2=−1t_2 = -1t2=−1 and tn=(n−3n−1)tn−2t_n = \left(\frac{n-3}{n-1}\right) t_{n-2}tn=(n−1n−3)tn−2 for n≥3n \ge 3n≥3. The, the value of the sum 1t2+1t4+1t6+⋯+1t2022+1t2024\frac{1}{t_2} + \frac{1}{t_4} + \frac{1}{t_6} + \dots + \frac{1}{t_{2022}} + \frac{1}{t_{2024}}t21+t41+t61+⋯+t20221+t20241 isCAT 2021 Slot 2For a sequence of real numbers x1,x2,......xnx_1, x_2, ...... x_nx1,x2,......xn, if x1−x2+x3−....+(−1)n+1xn=n2+2nx_1 - x_2 + x_3 - .... + (-1)^{n + 1} x_n = n^2 + 2nx1−x2+x3−....+(−1)n+1xn=n2+2n for all natural numbers n, then the sum x49+x50x_{49} + x_{50}x49+x50 equalsCAT 2019 Slot 2If (2n+1)+(2n+3)+(2n+5)+....+(2n+47)=5280(2n + 1) + (2n + 3) + (2n + 5) + .... + (2n + 47) = 5280(2n+1)+(2n+3)+(2n+5)+....+(2n+47)=5280, then what is the value of 1+2+3+...+n1 + 2 + 3 + ... + n1+2+3+...+n?